Google
 

Tuesday, July 29, 2008

Missionaries and Cannibals

Three missionaries and three cannibals come to a river and find a boat that holds two. If the cannibals ever outnumber the missionaries on either bank, the missionaries will be eaten.

How shall they cross?

Post your responses here.

3 comments:

Anonymous said...

Side A boat that holds drop at side B return

CCCMMM CC C C
CCMMM CC CC C
CMMM MM CM CM
CCMM MM MMM C
CCC CC CMMM C
CC CC CCCMMM --


EXPLANATION:

STEP 1: Two carnivals will go other side, one will return
Now at side A CARNIVAL -2, MAMMAL-3,side B CARNIVAL-1.
STEP 2: again two carnivals will go other side one will return
At side A CARNIVAL-1, MAMMAL-3, side B CARNIVAL-2.
STEP 3: now two mammal will go to other side and one carnival and one mammal will return .at side A CARNIVAL-2,MAMMAL-2;side B CARNIVAL-1,MAMMAL-1;
STEP 4: now 2 mammals will go other side and one carnival will return.
At side A CARNIVAL-3, side B MAMMAL-3
STEP 5: two carnivals will go other side and one will return
Side A CARNIVAL-2, side B MAMMAL-3, CARNIVAL-1;
STEP 6: two carnivals will go to other end.
Side A------, side B MAMMAL-3, CARNIVAL-3.

Anonymous said...

MISIONARIES AND CANNIBALS PROBLEM



NO OF M GO RETURN DROP
+
NO OF C


3M+3C 1M+1C 1C

1M

3M+2C

2C 1C(+1C)=2C

1C

3M+1C 2M 1M (+1C)=1M+1C

1C+1M

2M+2C 2M DROP 2M(+1M)=3M


1C

3C 2C 2C(+2M)=2C+2M


1M

1C+1M 1C+1M 1C+1M(2M+2C)
==
3M+3C

Anonymous said...

no of 'm' go return drop
+
no of 'c'


3m+3c 1m+1c 1c

1m

3m+2c 2c 1c(+1c)
=2c

1c

3m+1c 2m 1m

1c+1m
1c+1m

2c+2m 2m 2m(+1m)
=3m

1c

3c 2c 2c


1m

2c+2m

1c+1m 1c+1m 3c+3m

0c+0m 3c+3m

problem solved